F(-2)=3x^2-2x+5

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Solution for F(-2)=3x^2-2x+5 equation: 



(-2)=3F^2-2F+5

We move all terms to the left:

(-2)-(3F^2-2F+5)=0

We add all the numbers together, and all the variables

-(3F^2-2F+5)-2=0

We get rid of parentheses

-3F^2+2F-5-2=0

We add all the numbers together, and all the variables

-3F^2+2F-7=0

a = -3; b = 2; c = -7;
Δ = b2-4ac
Δ = 22-4·(-3)·(-7)
Δ = -80
Delta is less than zero, so there is no solution for the equation

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